2cos^2(4x)-6cos^2(2x)+1=0

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Solution for 2cos^2(4x)-6cos^2(2x)+1=0 equation:


Simplifying
2cos2(4x) + -6cos2(2x) + 1 = 0

Remove parenthesis around (4x)
2cos2 * 4x + -6cos2(2x) + 1 = 0

Reorder the terms for easier multiplication:
2 * 4cos2 * x + -6cos2(2x) + 1 = 0

Multiply 2 * 4
8cos2 * x + -6cos2(2x) + 1 = 0

Multiply cos2 * x
8cos2x + -6cos2(2x) + 1 = 0

Remove parenthesis around (2x)
8cos2x + -6cos2 * 2x + 1 = 0

Reorder the terms for easier multiplication:
8cos2x + -6 * 2cos2 * x + 1 = 0

Multiply -6 * 2
8cos2x + -12cos2 * x + 1 = 0

Multiply cos2 * x
8cos2x + -12cos2x + 1 = 0

Reorder the terms:
1 + 8cos2x + -12cos2x = 0

Combine like terms: 8cos2x + -12cos2x = -4cos2x
1 + -4cos2x = 0

Solving
1 + -4cos2x = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -4cos2x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -4cos2x = 0 + -1
-4cos2x = 0 + -1

Combine like terms: 0 + -1 = -1
-4cos2x = -1

Divide each side by '-4os2x'.
c = 0.25o-1s-2x-1

Simplifying
c = 0.25o-1s-2x-1

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